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6x^2=4704
We move all terms to the left:
6x^2-(4704)=0
a = 6; b = 0; c = -4704;
Δ = b2-4ac
Δ = 02-4·6·(-4704)
Δ = 112896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{112896}=336$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-336}{2*6}=\frac{-336}{12} =-28 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+336}{2*6}=\frac{336}{12} =28 $
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